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Cycle Time & Process Improvement

Once a program runs correctly and safely, the next question is: how fast can it run? This page covers cycle time analysis, where time actually goes, the levers you can pull, and the tool-life tradeoffs that separate smart optimization from reckless speeding.

Concept

Cycle time is the total time from program start (M30 reset) to part complete, including every move: rapid, feed, tool change, spindle start, and dwell. Optimization means reducing that total time — but not by simply cranking feed to maximum. Real optimization is about eliminating waste: shorter rapid paths, fewer tool changes, deeper cuts that stay within tool ratings, and smarter hole ordering.

Why It Matters

A 10-second saving per part on a 10,000-part run is 100,000 seconds = 27.8 hours of machine time. That is over a full week of available production time. Small per-part improvements compound across volume. But pushing feed too hard breaks tools, causes chatter, and scraps parts — optimization is a balance between cycle time, tooling cost, and quality.

How It Works

Where Time Actually Goes

CategoryExamplesTypical Share
Cutting timeFeed moves engaged with material40–60%
Rapid timeG00 moves between features15–30%
Tool changeATC carousel + spindle orientation5–15%
Spindle/dwellSpeed changes, dwells, coolant5–10%
Non-cutting setupPart probing, chip brush, air blast5–10%

Many beginners only look at cutting time. But on a typical mill program, rapid moves and tool changes can consume as much as the actual cutting. Optimizing only feed rate captures a fraction of the available gain.

Optimization Levers (in order of impact)

  1. Reduce tool changes — fewer tools = fewer ATC cycles. Can two operations share one tool? Can drilling and chamfering use the same tool?
  2. Optimize hole/feature order — drilling holes in a zig-zag order wastes rapid time. Order them nearest-to-nearest to minimize travel.
  3. Increase stepover — wider raster passes mean fewer passes across a pocket, reducing both rapid and cut time. Stay within tool and power limits.
  4. Increase feed — within the tool catalog. Most beginners run feed too conservative; running at 80% of catalog feed is safe.
  5. Increase depth of cut — take one deeper roughing pass instead of two shallow ones. Watch spindle power.
  6. Reduce rapid travel — program tool start positions closer to the part. Don't rapid across the full table for every hole.

The Tool Life Tradeoff

Every tool has a recommended cutting speed (SFM or m/min). Run faster and tool life drops sharply. The Taylor tool life equation: tool life is roughly inversely proportional to cutting speed raised to a power. Doubling speed can reduce tool life from 60 minutes to 6 minutes.

The break-even analysis: if increasing feed saves 4 seconds per pass but causes a tool to wear out twice as fast (adding a 30-second tool change every part instead of every other part), you lose 30 seconds to save 4. Optimize the whole process, not one number.

Cutting Speed Time / Cost Cycle time ↓ Tool cost ↑ Optimum
As speed increases, cycle time drops but tooling cost rises. The optimum is where total cost (cutting + tooling) is lowest — not at maximum speed.

Example

Worked example: A rectangular pocket requires 3 raster passes of 120 mm each. Current feed F300. Each pass = 120/300 = 0.4 min = 24 s. Total cutting = 72 s.

Increase feed to F360 (20% higher). Each pass = 120/360 = 0.333 min = 20 s. Total cutting = 60 s. Saving = 12 s per part.

On a 1,000-part run: 12 s × 1000 = 12,000 s = 3.3 hours saved. But check tool life: at F360, does the tool still last the expected 30 parts? If tool life drops from 30 parts to 15 parts, you change the tool twice as often. Each tool change adds 20 s to cycle time. Extra tool change cost: 1 change per part × 20 s = 20 s added. Net saving: 12 s saved − 20 s extra = −8 s. The faster feed costs more time than it saves.

Lesson: always verify the tool-life impact before increasing feed. The optimum is where the time saved exceeds the added tool-change cost.

Common Mistakes

Practice

1. 120 mm cut at F300 vs F360. Time saving?

Ans

At F300: 120/300 = 0.4 min = 24 s. At F360: 120/360 = 0.333 min = 20 s. Saving = 4 s per pass.

2. Name two non-cutting time savings.

Ans

(1) Optimize hole order to minimize rapid travel. (2) Reduce tool changes by combining operations or using one tool for multiple tasks.

3. Why not always run at maximum feed?

Ans

Tool life drops rapidly with speed. The cost of extra tool changes and scrap parts can exceed the time saved. The optimum balances cycle time against tooling cost.

4. Which optimization lever usually has the biggest impact?

Ans

Reducing tool changes and optimizing rapid travel order. A 15-second tool change saved per part beats a 2-second feed-rate improvement on a short cut.